Correct answer: (A) T maps L to a line.; (C) T⁻¹ maps C to a line.
Explanation
The unique map is T(z)=α(α−z)/(α+z), with pole −α. Because −α lies on L, its generalized-circle image contains ∞ and is a line. Also T(∞)=−α lies on the unit circle, so its inverse image contains ∞ and is a line. **A,C**.
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