Correct answer: (B) S₂ is true.; (C) S₂ is true and S₁ false.
Explanation
The Cayley transform gives g(D) = {Re w > 0}. Since g = 1+2f, f(D) = {Re w > −1/2}. Thus g(D)⊂f(D), but not conversely; f(0)=0 already lies outside g(D). S₂ is true and S₁ false, so **B,C**.
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