Rewrite the line as x=y−2. Intersections satisfy −y²=y−2, giving y=−2,1. The parabola is the right boundary. Area=∫ from −2 to 1 of (2−y−y²)dy=[2y−y²/2−y³/3] from −2 to 1=**9/2, C**.
More Multiple Integrals questions
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