Correct answer: (A) T properly contained in S implies L(T) properly contained in L(S).
Explanation
Proper set inclusion need not enlarge a span: T={e₁},S={e₁,2e₁} have identical spans. B follows because a span is already a subspace,and C is the sum-of-subspaces identity. In D,α=−2β−3γ and γ=−(α+2β)/3 give both inclusions. Thus **A**.
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