Soil and Water Conservation Engineering · Soil Mechanics · 2 marks · Numerical answer
An undisturbed soil sample has volume 100 cm³ and void ratio .60. Oven drying reduces mass from 185 g to 165 g without shrinkage. Soil specific gravity is 2.64. Find degree of saturation in percent, to two decimals.
Dry solids occupy $V_s=165/2.64=62.5$ cm³,so void volume is $100-62.5=37.5$ cm³,consistent with $e=37.5/62.5=.6$. Water mass is 20 g and its volume is 20 cm³. Degree of saturation is $S=V_w/V_v=20/37.5=.533333$,or **53.33%**.
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