Thermal efficiency is $\eta=1-Q_{out}/Q_{in}$. Rearranging gives $Q_{out}=(1-.56)(12.5)=.44(12.5)=\mathbf{5.50}$ kJ. Net work is 7.00 kJ, so input equals work plus rejected heat as required by the cyclic energy balance.
More Farm Power questions
GATE 2024 AG Q40– A three-cylinder, four-stroke diesel engine has bore73 mm, stroke78 mm, speed 2200 rpm,…
GATE 2023 AG Q16– Diesel turbocharger effectiveness increases when
GATE 2023 AG Q18– A four-stroke diesel inlet opens10° before TDC/closes40° after BDC. Exhaust opens25°…
GATE 2023 AG Q19– A tractor develops150 N·m at maximum power and has 20% reserve torque. Find peak torque in…
GATE 2023 AG Q53– A four-stroke engine uses diesel at 45 MJ/kg and BSFC260 g/(kW·hour),or B20 at 42.1 MJ/kg…
GATE 2022 AG Q14– The lowest temperature at which fuel ceases to flow is called .