A 5×20 cm seed drill has ground-wheel diameter .5 m. Laboratory calibration gives 320 g in 20 revolutions. Actual sowing uses185 kg in 2 ha. Find the seed-drop variation due to wheel skid. Use π=3.14.
Effective width=5(.20)=1 m. Calibration area=20(3.14)(.5)(1)=31.4 m², giving101.9108 kg/ha, or203.8217 kg over 2 ha. Reduction is $(203.8217-185)/203.8217\times100=\mathbf{9.23\%}$, **B**. The denominator is the no-skid laboratory prediction.
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