Specific energy=7.2/2=3.6 kWh/tonne. Bond’s relation with sizes in µm is $E=10W_i(1/\sqrt{500}-1/\sqrt{4750})$. Hence $W_i=3.6/[10(.0447214-.0145095)]=11.916$,matching **11.9,C**. Millimetres must first be converted to micrometres in this convention.
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