Two involute gears transmit1 kW at 20° pressure angle. Larger gear pitch diameter 20 cm and speed 600 rpm;one tooth pair carries load at a time. Find normal tooth force in N, to one decimal. Use π=3.14.
Pitch-line velocity=πDN/60=3.14(.20)(600)/60=6.28 m/s. Tangential force=P/v=1000/6.28=159.236 N. Since $F_t=F_n\cos20^\circ$,normal force=159.236/cos20°=**169.5 N**. Radial force is a different component.
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