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GATE 2024 ES – Question 37

Mathematics Foundation · Calculus · 2 marks · Multiple choice

Solve $y^{\prime\prime}-3y^{\prime}+2y=2e^{-x}$ with y(0)=2 and y′(0)=1.

  1. $e^{-x}/3-2e^x-e^{2x}/3$
  2. $e^x/3+2e^x-e^{2x}/3$
  3. $e^{-x}/3+2e^{-x}-e^{2x}/3$
  4. $e^{-x}/3+2e^x-e^{2x}/3$

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Correct answer: (D) $e^{-x}/3+2e^x-e^{2x}/3$

Explanation

The homogeneous characteristic roots are1,2. A particular solution $Ae^{-x}$ gives $(1+3+2)A=2$,so A=1/3. Write $y=e^{-x}/3+Be^x+Ce^{2x}$. Initial conditions give $B+C=5/3$ and $B+2C=4/3$,so C=−1/3,B=2. Therefore **D**.

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