The figure has a 1-hour rising limb and 2-hour falling limb, so total base is 3 h=10800 s. Excess volume=.01(540×10000)=54000 m³. Equate triangular hydrograph volume $Q_p(10800)/2=54000$ to obtain **10.0 m³/s**. “2-hour” describes excess-rain duration, not the hydrograph base.
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