Correct answer: (D) Set I: vibrational band of Y; Set II: rotational band of X.
Explanation
Set I has a $0^+$ ground state, a $2^+$ state at 600 keV and a $0^+,2^+,4^+$ multiplet at 1200 keV. These are the zero-, one- and two-phonon pattern of a quadrupole vibrator in an even-mass nucleus, so it belongs to Y. Set II has half-integer spins $7/2,11/2,15/2,19/2,23/2$ whose energies follow rotational $J(J+1)$ spacings above a band head; it belongs to odd-mass X. Thus D.
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