A player scores a basket with probability 0.1 on each independent attempt. On two attempts, find the probability of scoring only on the second, to two decimal places.
“Only on the second” requires a miss first and a success second. The probabilities are $1-0.1=0.9$ and 0.1. Independence allows multiplication: $P=0.9(0.1)=0.09$. The two-success and first-only outcomes are excluded.
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