A second-order system has closed-loop poles $s=-3\pm j4$. Find the time of the first maximum of its unit-step response, in seconds, to two decimal places.
For the standard underdamped second-order step response, the damped oscillation frequency is the imaginary part of the poles, $\omega_d=4$ rad/s. The first peak occurs at $t_p=\pi/\omega_d=\pi/4=0.785398$ s, rounding to 0.79 s. The real part sets the decay rate rather than the peak spacing.
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