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GATE 2020 MA – Question 37

Linear Algebra · Vector Spaces and Linear Transformations · 2 marks · Multiple choice

On a nonzero finite-dimensional complex vector space V, a linear T satisfies Range(T) = Nullspace(T). Which statement is FALSE?

  1. Dimension of V is even.
  2. Zero is the only eigenvalue.
  3. Both 0 and 1 are eigenvalues.
  4. $T^2=0$

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Correct answer: (C) Both 0 and 1 are eigenvalues.

Explanation

Range(T) lies in Nullspace(T), so T² = 0. Every eigenvalue λ then satisfies λ² = 0 and is zero; 1 cannot be an eigenvalue. Rank–nullity with equal rank and nullity makes dim V twice the rank and therefore even. Thus A, B and D are true, while C is false.

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