Correct answer: (D) If $W_1\ne V$, then $\operatorname{span}(V\setminus W_1)=V$.
Explanation
Take v outside proper subspace W₁. For every w∈W₁, both v and v + w lie outside W₁, so $w=(v+w)-v$ belongs to the span of its complement. The complement itself is already in that span, so all V is spanned, proving D. The other statements incorrectly replace a subspace sum by a union or assume cancellation of subspace sums.
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