GATE 2017 CS (CS2) – Question 58
X is Poisson with mean 5. Find E[(X+2)²].
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Correct answer: 54.0 to 54.0
Explanation
For Poisson X, E[X]=Var(X)=5. Therefore E[X²]=Var(X)+(E[X])²=5+25=30. Expanding gives E[(X+2)²]=E[X²]+4E[X]+4=30+20+4=54.