The shown catheter pressure sensor uses a diaphragm with four identical Wheatstone-bridge gauges. Each has nominal resistance 10 kΩ, gauge factor 40 and Young’s modulus 10 MPa. Opposite arms experience +ε and the other opposite arms −ε, with small ε>0. Excitation is 2 V. Find sensitivity Vₒ/σ in V/MPa.
For the shown full active bridge and polarity, the output is excitation times fractional gauge resistance change: Vo=2Gε. Hooke’s law gives σ=Eε, so Vo/σ=2G/E=2×40/10=8 V/MPa. The nominal ten-kilohm resistance cancels because the bridge measures a resistance ratio.
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