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GATE 2017 EE (EE2) – Question 8

General Aptitude · Quantitative Aptitude: Data Interpretation, Arithmetic and Number Computation · 2 marks · Multiple choice

X is a 30-digit number beginning with digits 47. How many digits does $X^3$ have?

  1. 90 digits
  2. 91 digits
  3. 92 digits
  4. 93 digits

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Show answer and explanation

Correct answer: (A) 90 digits

Explanation

The leading digits imply $4.7\times10^{29}\le X<4.8\times10^{29}$. Cubing gives a lower bound $103.823\times10^{87}$ and upper bound $110.592\times10^{87}$.

Both lie between $10^{89}$ and $10^{90}$. Every integer in that interval has 90 digits. Therefore **X³ has 90 digits, A**.

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