GATE 2017 EE (EE2) – Question 63

Power Systems · Voltage and Frequency control, Power factor correction · 2 marks · Numerical answer

Parallel generating units rated 300 MW and 400 MW have no-load-to-full-load governor speed regulations 6% and 4%, respectively. With free governor action they share 600 MW. The larger unit’s share in MW is ________.

Practise this question in The GATE Grind →

Show answer and explanation

Correct answer: 395 to 405

Explanation

With a common no-load frequency setting, each unit's load increment for a given frequency drop is proportional to its rating divided by its per-unit droop.

The two sensitivities are 300/0.06=5000 and 400/0.04=10000, so the larger unit takes twice the smaller unit's load. Dividing 600 MW in ratio 1:2 gives **400 MW** for the larger unit.

The equal no-load reference is the standard assumption behind the supplied droop-sharing data.

More Voltage and Frequency control, Power factor correction questions

GATE 2016 EE (EE2) Q51 – An industry consumes 500 kVA at 0.8 lagging pf. A synchronous motor taking 100 kW is added…
GATE 2025 EE Q63 – Using shunt capacitors, the power factor of a 3-phase, 4 kV induction motor (drawing 390…
GATE 2024 EE Q47 – Which of the following options is/are correct for the Automatic Generation Control (AGC)…
GATE 2022 EE Q56 – Two generating units rated for 250 MW and 400 MW have governor regulations of 6% and 6.4%,…
GATE 2020 EE Q33 – A single 50 Hz synchronous generator on droop control was delivering 100 MW power to a…
GATE 2020 EE Q56 – A cylindrical rotor synchronous generator with constant real power output and constant…

All Voltage and Frequency control, Power factor correction questions →