The triangle is 0≤x≤y≤1. Integrate first over y for a fixed x, where x≤y≤1: $$V=\int_0^1(1-x)e^x\,dx.$$ An antiderivative is (2−x)eˣ. Evaluating at 1 and 0 gives **e−2≈0.718282**, within 0.70–0.76.
More Calculus: Mean value theorems, Theorems of integral calculus, Evaluation of definite and improper integrals, Partial derivatives, Multiple integrals, Fourier series questions
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