An uncharged solute has a 1.6-fold concentration difference across a membrane. Find energy for uphill active transport in cal/mol, nearest integer, at 37°C. R = 1.987 cal/(mol K).
The concentration contribution to chemical-potential difference is $\Delta G=RT\ln(C_{high}/C_{low})$. For uncharged solute there is no electrical term. With T ≈ 310 K, $\Delta G=1.987(310)\ln1.6\approx290$ cal/mol. The positive sign is the required uphill work.
More Biochemistry: Biomolecules, biological membranes, channels and pumps, molecular motors, action potential and transport questions
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