Yeast biomass $C_6H_{10}O_3N$ grows on glucose as $$\begin{aligned}C_6H_{12}O_6+0.48NH_3+3O_2\\\to0.48C_6H_{10}O_3N+3.12CO_2+4.32H_2O.\end{aligned}$$ Find glucose needed in kg, nearest integer, to produce 50 g/L biomass in a 100000 L batch reactor.
Target biomass is 50(100000) = 5000000 g. Its formula mass is 6(12)+10+3(16)+14 = 144 g/mol. Each mole glucose (180 g) yields 0.48 mol biomass, or 69.12 g. Required glucose is $5000000(180/69.12)=13020833$ g = 13020.83 kg, rounding to 13021 kg.
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