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GATE 2020 PI – Question 61

Operations Research and Operations Management · Engineering Economy and Costing · 2 marks · Numerical answer

Machine A has cost CA(x)=10000+170x+x² rupees; B costs CB(x)=15000+400x. Find the minimum positive integer output at which B is preferred.

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Correct answer: 250 to 250

Explanation

B is cheaper when15000+400x<10000+170x+x², or x²−230x−5000>0. The positive break-even root is(230+√72900)/2=250. At250 costs tie; strict preference begins at251. The official singleton answer is250, using the break-even threshold as the intended minimum. That grading is retained and the tie distinction is explicit.

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