Geomechanics and Ground Control · Engineering Mechanics · 2 marks · Numerical answer
Blocks P and Q weigh100 and200 kN. They are connected over a fixed frictionless pulley as drawn. Friction coefficient P–Q is0.4 and Q–floor0.3. Find minimum horizontal force F pulling Q in kN, as an integer.
Relative motion makes P slide left as Q moves right. Friction at their interface is0.4×100=40 kN; P equilibrium gives string tension40 kN. Q is opposed by that tension, a further40 kN interface-friction force and floor friction0.3(100+200)=90 kN. Hence F=40+40+90=170 kN.
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