Horizontal resultant is 100−100cos 45°=29.289 N and vertical resultant 100sin 45°=70.711 N. Magnitude is√(29.289²+70.711²)=76.537 N. Divide by 10 kg to get 7.6537 m/s², or 7.65. The sketch represents the stated in-plane forces.
More Engineering Mechanics questions
GATE 2023 MN Q31– Punch a 10 mm diameter hole through a 5 mm thick rock plate as shown. The rock plate yield…
GATE 2023 MN Q49– A dozer pushes a 100 kg cable spool at constant speed up a 20° incline. The road contact A…
GATE 2023 MN Q52– A UAV of mass 1.2 kg carries a 2 kg payload vertically through 100 m in 10 s at constant…
GATE 2022 MN Q20– For the pin-jointed truss and loads shown, find axial force in member BD in kN.
GATE 2022 MN Q48– Two weightless cables of equal length and area support the ends of a light 1 m horizontal…
GATE 2021 MN Q35– A vehicle travelling 12 m/s skids without rolling to rest over 15 m on a level road.…
