Mining Geology, Mine Development and Surveying · Mine Surveying · 2 marks · Numerical answer
Shaft A has surface coordinates N 670, W 150 m, surface RL 250 m and depth 200 m. Shaft B has N 170, E 50 m, surface RL 209 m and depth 149 m. Find the downward gradient angle of the line joining their bottoms, in degrees to two decimals.
Bottom levels are A:250−200=50 m and B:209−149=60 m. The horizontal coordinate differences are 500 m northing and 200 m easting, giving plan distance √(500²+200²)=538.5165 m. The 10 m fall from B to A gives angle atan(10/538.5165)=1.0638°, or 1.06°. Use bottom levels rather than the surface-level difference.
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