Surface Environment, Mine Ventilation and Underground Hazards · Mine Ventilation · 2 marks · Numerical answer
A three-shift coal mine produces 400 t/day from panel A and 200 t/day from B, both with face OMS 1.0. Parallel-panel resistances are 0.6 and 0.5 N·s²/m⁸. At the minimum ventilation quantities under the regulation cited in the source as CMR 2018, find regulator resistance in N·s²/m⁸, to two decimals.
Compare 6 m³/min per person on the largest shift with 2.5 m³/min per daily tonne. The tonnage criterion governs: A needs 1000 m³/min=16.667 m³/s; B needs 500 m³/min=8.333 m³/s. A’s pressure drop is 0.6×16.667²≈166.667 Pa. Equal pressure in B requires total resistance 166.667/8.333²=2.4. Add regulator 2.4−0.5=1.90 to B. The source’s CMR 2018 label refers to the coal-mine regulatory ventilation criterion.
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