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GATE 2015 EC – Question 4

General Aptitude · Quantitative Aptitude: Arithmetic and Number Computation · 1 mark · Multiple choice

Operators $\square$, $\Diamond$ and $\rightarrow$ are defined by: $a \square b = \frac{a - b}{a + b}$; $a \Diamond b = \frac{a + b}{a - b}$; $a \rightarrow b = ab$.

Find the value of $(66 \square 6) \rightarrow (66 \Diamond 6)$.

  1. -2
  2. -1
  3. 1
  4. 2

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Correct answer: (C) 1

Explanation

First, $66 \square 6 = \frac{60}{72} = \frac{5}{6}$ and $66 \Diamond 6 = \frac{72}{60} = \frac{6}{5}$. Then the product operator gives $\frac{5}{6} \times \frac{6}{5} = 1$.