GATE 2026 ME – Question 2
If a positive real $x$ satisfies the following equation
$$\log_2 x + \log_{\sqrt{2}} x = 48,$$
then the value of $x$ is __________.
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Correct answer: (A) $2^{16}$
Explanation
Since $\log_{\sqrt{2}} x = \frac{\log_2 x}{\log_2 \sqrt{2}} = 2\log_2 x$, the equation becomes $3\log_2 x = 48$. So $\log_2 x = 16$ and $x = 2^{16}$.