GATE 2025 CE (CE2) – Question 61
The analyses results of a water sample are given below. The non-carbonate hardness of the water (in mg/L) as CaCO$_3$ is ______ (in integer).
Ca$^{2+}$ = 150 mg/L as CaCO$_3$
Mg$^{2+}$ = 40 mg/L as CaCO$_3$
Fe$^{2+}$ = 10 mg/L as CaCO$_3$
Na$^+$ = 50 mg/L as CaCO$_3$
K$^+$ = 10 mg/L as CaCO$_3$
CO$_3^{2-}$ = 120 mg/L as CaCO$_3$
HCO$_3^-$ = 30 mg/L as CaCO$_3$
Cl$^-$ = 50 mg/L as CaCO$_3$; Other anions were not analysed.
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Correct answer: 50
Explanation
The hardness is caused by the divalent cations: $150 + 40 + 10 = 200$ mg/L as CaCO₃. The alkalinity is $120 + 30 = 150$ mg/L as CaCO₃. The carbonate hardness is the smaller of the total hardness and the alkalinity, 150 mg/L, so the non-carbonate hardness is $200 - 150 = 50$ mg/L as CaCO₃.