GATE 2022 AE – Question 15
For two-dimensional potential flow over a cylinder at free-stream speed $U_\infty$, the maximum cylinder-surface speed is
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Correct answer: (C) $2U_\infty$
Explanation
For the 2-D potential flow of a uniform stream $U_\infty$ past a circular cylinder of radius $a$ (uniform flow plus a doublet), the velocity components at the surface $r=a$ are
$$u_r=0,\qquad u_\theta=-2U_\infty\sin\theta .$$
The speed on the surface is therefore
$$|u_\theta|=2U_\infty|\sin\theta| .$$
It is largest at $\theta=\pm90^\circ$ (top and bottom of the cylinder), where $\sin\theta=\pm1$:
$$V_{max}=2U_\infty\quad(\text{option C}).$$
(At the stagnation points, $\theta=0^\circ$ and $180^\circ$, the speed is zero.)