GATE 2025 CY – Question 33
The specific rotation of enantiomerically pure (S)-2-butanol is +14°. The specific rotation of enantiomeric mixture of 2-butanol obtained from an asymmetric reduction of 2-butanone is found to be +7°. The percentage of (R)-2-butanol present in the reaction mixture is _____ (in integer).
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Correct answer: 25
Explanation
**Optical purity.** The specific rotation of the mixture divided by that of the pure enantiomer gives the enantiomeric excess (ee):
$$ee=\frac{[\alpha]_{mix}}{[\alpha]_{pure}}=\frac{+7}{+14}=0.50=50\% .$$
The positive sign shows that the (S) enantiomer is in excess (pure S is +14°).
**Composition.** $ee=x_S-x_R=0.50$ and $x_S+x_R=1$:
$$x_R=\frac{1-0.50}{2}=0.25 .$$
The mixture contains **25%** of the (R)-2-butanol.