GATE 2021 ME (ME2) – Question 38
Consider the following differential equation $\frac{dy}{dx}=\frac{y}{1+y}$. The solution of the equation that satisfies the condition $y(1)=1$ is
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Correct answer: (C) $ye^y=e^x$
Explanation
Separate variables near the positive initial value: $(1+1/y)dy=dx$. Integrating gives y+ln y=x+C.
The initial condition gives C=0. Exponentiating yields **yeʸ=eˣ (C)**, which also satisfies the original differential equation.