GATE 2021 CE (CE2) – Question 41
A 6 m wide rectangular channel carries 20 m³/s. With g=9.81 m/s², find the depth at which specific energy is minimum.
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Correct answer: (B) 1.04 m
Explanation
Specific energy is $E=y+q^2/(2gy^2)$ with q=Q/b. Setting dE/dy=0 gives critical depth $y_c=(q^2/g)^{1/3}=[(20/6)^2/9.81]^{1/3}=1.04239$ m. Hence **1.04 m (B)**.