GATE 2021 CY – Question 9
Define $\lambda(p,q)=\begin{cases}(p-q)^2,&p\ge q\\p+q,&p<q.\end{cases}$ Evaluate $\dfrac{\lambda(-(-3+2),(-2+3))}{(-(-2+1))}$.
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Correct answer: (B) $0$
Explanation
The arguments are −(−3+2)=1 and −2+3=1. Since p≥q at equality, use λ(p,q)=(p−q)², giving λ(1,1)=0. The denominator is −(−2+1)=1.
Therefore the expression is **0/1=0, B**.