The quantity of cobalt ore $Co_3(AsO_4)_2\cdot H_2O$ needed to obtain 1 kg Co is ______ kg (two decimal places). Atomic weights: Co 59, As 75, O 16, H 1.
The formula mass of Co3(AsO4)2·H2O is 3×59+2×(75+4×16)+18=473 g/mol. Each mole contains 177 g cobalt, so the cobalt mass fraction is 177/473. To obtain 1 kg cobalt requires 473/177=2.6723 kg ore, or **2.67 kg** to two decimals, assuming quantitative recovery.