The GATE Grind

GATE 2026 IN – Question 22

Analog Electronics · Diodes and transistor circuits · 1 mark · Multiple choice

In the circuit shown, the BJT has $\beta=100$. The base-emitter junction voltage is $0.65\ \mathrm V$. The quiescent collector current $I_C$ is ________ mA.

Diagram for GATE 2026 IN question 22
  1. 0.365
  2. 0.435
  3. 0.625
  4. 0.862

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Show answer and explanation

Correct answer: (A) 0.365

Explanation

Replace the two 5 kΩ base-divider resistors by their Thevenin equivalent: $V_{th}=2.5\ \mathrm V$ and $R_{th}=2.5\ \mathrm{k}\Omega$.

Since $I_E=(\beta+1)I_B$, the base loop gives $2.5=I_B(2500)+0.65+101I_B(5000)$. Thus $I_B=1.85/507500=3.645\ \mu\mathrm A$ and $I_C=100I_B=0.3645\ \mathrm{mA}$.

As a check, $V_C\approx3.177\ \mathrm V$ and $V_E\approx1.841\ \mathrm V$, leaving $V_{CE}\approx1.336\ \mathrm V$, consistent with active operation. The correct option is **A**.