The GATE Grind

GATE 2024 IN – Question 48

Communication and Optical Instrumentation · Analog and digital communication · 2 marks · Multiple choice

In the ultrasonic measurement system shown, transmitter T sends $x(t)=\cos(2\pi f_1t)$ V toward an object vibrating as $m(t)=0.5\sin(2\pi f_2t)$ V. Neglecting other phase shifts, receiver R detects $y(t)=\cos[2\pi f_1t+\beta\cos(2\pi f_2t)]$ V. Frequency sensitivity is 500 Hz/V, $f_1=40$ kHz, and $f_2=1$ kHz. The modulation index $\beta$ and frequency deviation, respectively, are

Diagram for GATE 2024 IN question 48
  1. $0.25,\ \pm250$ Hz
  2. $0.5,\ \pm500$ Hz
  3. $1,\ \pm1000$ Hz
  4. $0.75,\ \pm1000$ Hz

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Correct answer: (A) $0.25,\ \pm250$ Hz

Explanation

The peak frequency deviation is sensitivity times message amplitude: $\Delta f=500(0.5)=250$ Hz. The modulation index is $\beta=\Delta f/f_2=250/1000=0.25$.

Thus the pair is **0.25 and ±250 Hz, A**.