GATE 2023 IN – Question 65
The source $V_s=10\sqrt2\sin(20000\pi t)$ V has internal resistance 50 Ω. The RMS current through R in the circuit shown is ______ mA (one decimal place).
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Correct answer: 99.0 to 101.0
Explanation
At $\omega=20000\pi$, the given L and C have reactances +1 Ω and −1 Ω, which cancel. Add the 50 Ω source resistance and both 25 Ω resistors to get 100 Ω. The source RMS is 10 V, so $I_{rms}=10/100=0.1$ A, or **100.0 mA**.