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GATE 2018 ME (ME2) – Question 33

Thermodynamics · Zeroth, first and second laws, work, heat and energy changes · 1 mark · Numerical answer

An engine follows the shown reversible cycle. Find work output in kJ/cycle, to two decimal places.

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Correct answer: 62.00 to 63.00

Explanation

Cycle work equals enclosed p–V area. The clockwise triangle gives positive output: $$W=\tfrac12(650-400)(2.5-2)=62.50\ \mathrm{kJ}.$$ Here kPa·m³ equals kJ.