GATE 2016 ME (ME2) – Question 28
The heat removal rate from a refrigerated space and the power input to the compressor are 7.2 kW and 1.8 kW, respectively. The coefficient of performance (COP) of the refrigerator is ______
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Correct answer: 3.9 to 4.1
Explanation
Refrigerator COP is desired cooling rate divided by work-input rate. Thus COP=7.2/1.8=**4.0**. Heat rejected would be7.2+1.8=9kW but is not the numerator for a refrigerator; it would be used for heat-pump COP.