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GATE 2021 ME (ME2) – Question 31

Thermal Engineering Applications · Refrigeration and heat pump cycles · 1 mark · Numerical answer

Consider an ideal vapour compression refrigeration cycle working on R-134a refrigerant. The COP of the cycle is 10 and the refrigeration capacity is 150 kJ/kg. The heat rejected by the refrigerant in the condenser is _____ kJ/kg (round off to the nearest integer).

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Correct answer: 165

Explanation

COP=qL/w, so compressor work is 150/10=15 kJ/kg. The cycle first law gives qH=qL+w.

Thus condenser heat rejection is 150+15=**165 kJ/kg**.