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GATE 2014 EC (EC2) – Question 33

Communications · Analog Communications · 1 mark · Numerical answer

In sinusoidal AM without overmodulation, envelope maximum and minimum are 3 V and 1 V. Find modulation index µ.

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Correct answer: 0.45 to 0.55

Explanation

For ordinary AM without overmodulation, Emax=Ac(1+µ) and Emin=Ac(1−µ). Dividing their difference by their sum gives µ=(Emax−Emin)/(Emax+Emin)=(3−1)/(3+1)=**0.5**.