GATE 2014 EC (EC4) – Question 17
Find the magnitude of current through R₂ (mA) in the circuit shown.

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Correct answer: 2.79 to 2.81
Explanation
Let I in mA flow through R2left-to-right and return through R4. The left shunt current is10−I, giving left voltage2(10−I)V. The right shunt current is I−2, giving right voltage4(I−2)V. The series bridge drop is(1+3)I=4I. Thus20−2I=4I−8+4I, giving **I=2.8mA**.