GATE 2014 EE (EE2) – Question 38
Find the minimum of $x^3-3x^2-24x+100$ on [−3,3].
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Correct answer: (B) 28
Explanation
The derivative is3x²−6x−24=3(x−4)(x+2),so only x=−2is a stationary point in the interval. Check it and both endpoints:f(−3)=118,f(−2)=128,f(3)=28. The smallest is **28,B**,at the right endpoint; the interior stationary point is a maximum.