Correct answer: (B) Failure is cup-and-cone fracture.; (C) True stress exceeds engineering stress at any finite strain.; (D) Complete unloading after stress above yield does not restore original dimensions.
Explanation
Ductile mild steel commonly forms a cup-and-cone fracture. In tensile deformation its current area decreases, so force/current area exceeds force/original area for positive finite strain. Plastic strain beyond yield remains after unloading. Thus **B,C,D**. Linear proportional behavior ends at the proportional limit; the elastic range need not be entirely linear, so A is overbroad. C is understood for tensile strain before complete rupture.
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