Manufacturing Processes I · Casting · 2 marks · Numerical answer
A cylindrical casting has diameter 10 cm and mass 12.56 kg. Material density is 7.85 × 10⁻³ kg/cm³. Chvorinov exponent n = 2 and solidification time 12 min. Find Chvorinov constant in min/cm² to two decimals.
Volume is V = 12.56/0.00785 = 1600 cm³. With r = 5 cm, height is $L=1600/(25\pi)$ cm. Total exposed area is $A=2\pi rL+2\pi r^2=640+50\pi=797.0796$ cm². Chvorinov gives $C=t_s/(V/A)^2=12/(1600/797.0796)^2=\mathbf{2.98}$ min/cm².
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