Manufacturing Processes I · Casting · 2 marks · Numerical answer
A sand casting cavity measures60×40×20 cm and has a cylindrical side blind riser with height equal to diameter. Riser solidification time must exceed casting time by25%. Under Chvorinov’s rule, find riser diameter in cm (one decimal).
Casting volume is 60×40×20 = 48000 cm³. Its six-face area is 2(60×40 + 40×20 + 60×20) = 8800 cm². Thus casting modulus is 48000/8800 = 5.4545 cm. Since solidification time scales with modulus squared, the riser modulus must be √1.25 times this. For a blind cylindrical riser with H=D and the stated surface-area convention, modulus is D/6. Hence D = 6(5.4545)√1.25 = 36.59 cm, or 36.6 cm.
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