Manufacturing Processes I · Casting · 2 marks · Numerical answer
An 80 mm cube casting undergoes volumetric solidification shrinkage 4.5% and solid contraction 2%. Assume uniform cooling in every direction. Find the required cubical pattern side (two decimal mm).
The intended total volume factor is $(1-0.045)(1-0.02)=0.9359$. If pattern side is a, $a^3(0.9359)=80^3$, so $a=80/(0.9359)^{1/3}\approx\mathbf{81.79}$ mm. This treats both supplied shrinkages as allowances in the stated size calculation; in practical risered casting, solidification shrinkage is normally fed by a riser while pattern shrinkage allowance concerns solid contraction.
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